lim_x 1 0.05em tan ⁡(x^2-1)x-1 is equal to

Question

Accepted Answer

Correct answer: A. (a) : lim_x 1 0.05em tan ⁡(x^2-1)x-1 ( 00 ) form ) Using L' Hospital rule, we get lim_x 1 0.05em 2x sec^2 ⁡(x^2-1)1= lim_x 12x sec^2 ⁡(x^2-1) =2 1 sec^2 ⁡ (0 )=2 1 1=2.

$lim_{x \to 1} \frac{tan ( x ^{2} - 1 )}{x - 1} is equal to$

Solution

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