The negation of p ( ∼p ∨q ) is

Question

Accepted Answer

Correct answer: D. (d) : The given boolean expression can be written as, ( ∼p ) ∨ ( ( ∼p ) ∨q ) = ( ( ∼p ) ∨ ( ∼p ) ) ∨q [By associativity of 'OR' operation] = ( ∼p ) ∨q [ ∵A ∨A=A ] Now, the negation of the given expression = ∼ ( ( ∼p ) ∨q ) = ( ∼ ( ∼p ) ) ∧ ( ∼q ) [By De Morgan's law] =p ∧ ( ∼q ) [ ∵ ∼ ( ∼p )=p, for boolean p ]

$The negation of p \to (\sim p \lor q) is$

Solution

More Mathematical Logic & Miscellaneous Algebra PYQs