The area of a triangle with vertices (-3 ,0 ), (3 ,0 ) and (0 ,k ) is 9 sq. units, the value of k is

Question

Accepted Answer

Correct answer: C. (c) : Vertices of triangle are (-3 ,0 ) , (3 ,0 ) and (0 ,k ). Area of triangle =9 sq. units (given) ⇒ 12(-3013010k1)=9 ⇒ 12 |-3 (0-k )-0+1 (3k-0 ) |=9 ⇒ 12 |3k+3k |=9 ⇒ |3k |=9 ⇒3k=9 or 3k=-9 ⇒k=3 or k=-3

$The area of a triangle with vertices (- 3, 0), (3, 0) and (0, k) is 9 sq. units, the value of k is$

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