The value of vmatrix1& _xy& _xz\ _yx&1& _yz\ _zx& _zy&1 vmatrix=

Question

Accepted Answer

Correct answer: B. (b): (1 log_x ⁡y log_x ⁡z log_y ⁡x1 log_y ⁡z log_z ⁡x log_z ⁡y1 ) Expanding along first row, we get =1(1- log_z ⁡y log_y ⁡z)- log_x ⁡y( log_y ⁡x-) ( log_y ⁡z log_z ⁡x)+ log_x ⁡z( log_y ⁡x log_z ⁡y- log_z ⁡x) =1 (1-1 )- log_x ⁡y( log_y ⁡x- log_y ⁡x) + log_x ⁡z( log_z ⁡x- log_z ⁡x)=0

$The value of 1 lo g_{y} x lo g_{z} x lo g_{x} y 1 lo g_{z} y lo g_{x} z lo g_{y} z 1 =$

Solution

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