If ( )=( cos ⁡ - sin ⁡ 0 sin ⁡ cos ⁡ 0001) (xyz ), then x^2+y^2+z^2 =

Question

Accepted Answer

Correct answer: A. (a) ( )=( cos ⁡ - sin ⁡ 0 sin ⁡ cos ⁡ 0001) (xyz ) ⇒ ( )=(x cos ⁡ -y sin ⁡ x sin ⁡ +y cos ⁡ z) ∴ =x cosx-y sin … … (i ) =x sin +y cos … . . ( ii ) =z Equation (i) )^2+ ( ii )^2 : ^2+ ^2=x^2+y^2 Now, x^2+y^2+z^2 = ^2+ ^2+ ^2z

$If (α β γ) = (cos θ - sin θ 0 sin θ cos θ 0001) (x y z), then \frac{x ^{2} + y ^{2} + z ^{2}}{γ} =$

Solution

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