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JEE Previous Year Question

$The equation of directrix of parabola x^{2} + 8 x + 12 y + 4 = 0 is$

Topic: JEE PYQ

Answer: C. Full step-by-step solution below.

A $y + 4 = 0$
B $y - 1 = 0$
C $y - 4 = 0$
D $y - 2 = 0$

Correct answer: C

Solution

(c) Given parabola is x^{2} + 8 x + 12 y + 4 = 0 This can be written as (x + 4)^{2} = 4 (- 3) (y - 1) Here, V = (- 4, 1) and equation of Directix, Y = 4 or y - 4 = 0

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