Given three indentical bags each containing 10 Balls, whose colours are as follows: Red Blue Green Bag I 3 2 5 Bag II 4 3 3 Bag III 5 1 4 A person chooses a bag at random and takes out a ball. If the…

Question

Given three indentical bags each containing 10 Balls, whose colours are as follows:

Red
Blue
Green
Bag I
3
2
5
Bag II
4
3
3
Bag III
5
1
4
A person chooses a bag at random and takes out a ball. If the ball is Red, the probability that it is
from bag I is p and if the ball is Green, the probability that it is from bag III is

q

, then the value
of

(\frac{1}{p} + \frac{1}{q})

is:

Accepted Answer

Correct answer: C. (c) Probability that a Red ball comes from Bag I (p ) : p(B_1/R)= p (B_1 ) p(R/B_1)p (R ) Substituting the values, p(B_1/R)= 13 310 13 310+ 13 410+ 13 510 Simplify to find p : = 110 13 (1.2 )= 14 So, p= 14. Probability that a Green ball comes from Bag III ( q ): p(B_3/G)= p (B_3 ) p(G/B_3)p (G ) Substitute the values, p(B_3/G)= 13 410 13 510+ 13 310+ 13 410 Simplify to find q : = 215 13 1.2= 13 So, q= 13. Calculation of ( 1p+ 1q) : 1p=4 , 1q=3 Therefore, ( 1p+ 1q)=4+3=7

Solution

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