If , , are the roots of the equation x^3-5x^2-2x+24=0 then βγ + γα + αβ =

Question

Accepted Answer

Correct answer: D. (d) We have equation x^3-5x^2-2x+24=0 Here, + + =5 αβ+ βγ+ γα=-2 , αβγ=-24 Here βγa+ γαb+ αβg= ( αβ+ βγ+ γα )^2-2 αβγ ( + + ) αβγ = -24424= -616

$If α, β, γ are the roots of the equation x^{3} - 5 x^{2} - 2 x + 24 = 0 then \frac{βγ}{α} + \frac{γα}{β} + \frac{αβ}{γ} =$

Solution

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