The sum of all the real numbers satisfying the equation x^2+ |x-3 |=4 is

Question

Accepted Answer

Correct answer: B. (b) Given equation is x^2+ |x-3 |=4 Case I: x>3, then (x-3 ) is positive. ∴x^2+x-3=4 x^2+x-7=0 Apply quadratic formula, x= -1 292 ∴ No solution Case II: x<3, then (x-3 ) is negative ∴x^2-x+3=4 x^2-x-1=0 Apply quadratic formula x= 1 52 ∴ Sum of all real number satisfy ray the equal 1+ 52+ 1- 52=1

$The sum of all the real numbers satisfying the equation x^{2} + | x - 3 | = 4 is$

Solution

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