If x^2+2 px-2p+80 for all real values of x, then the set of all possible values of p is

Question

If x^2+2 px-2p+8>0 for all real values of x, then the set of all possible values of p is

Accepted Answer

Correct answer: D. (d) For any quadratic expression P (x ) P (x )>0 ∀ xR ⇒D<0 ,a>0 D= (2p )^2-4 (8-2p )<0 4p^2-32+8p<0 (p+4)(p-2)<0 ∴p ∈ (-4 ,2 )

$If x^{2} + 2 px - 2 p + 8 > 0 for all real values of x, then the set of all possible values of p is$