Let S_n denote the sum of the first n terms of an A .P. If S_4=16 and S_6=-48 then S_10 is equal to :

Question

Accepted Answer

Correct answer: C. (c) JEE Main 2019 Given S_4=16 and S_6=-48 ⇒2 (2a+3d )=16 ⇒2a+3d=8 … (i ) and 3 [2a+5d ]=-48 ⇒2a+5d=-16 ⇒2d=-24 [using equation (i )] ⇒d=-12 and a=22 ∴S_10= 102 (44+9 (-12 ) )=-320

$Let S_{n} denote the sum of the first n terms of an A . P . If S_{4} = 16 and S_{6} = - 48 then S_{10} is equal to :$

Solution

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