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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Sequence & Series · Set 4 (Q91-120)
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91.
Let Sn=21+61+121+201+… upto n terms. If the sum of the first six terms of an A.P. with first term -p and common difference p is 2026S2025, then the absolute difference betwen 20th and 15th terms of the A.P. is
(1)20
(2)90
(3)45
(4)25
92.
If θ=6π, then the 10th term of the series 1+(cosθ+isinθ)1+(cosθ+isinθ)2+… is
(1)-1
(2)-i
(3)21+23i
(4)1
93.
If the roots α,β,γ of the equation x3−6x2+px+10=0 are in arithmetic progressions, then α3+β3+γ3=
(1)132
(2)134
(3)629
(4)645
94.
Let S1 be the sum of first 2nterms of an arithmetic progression. Let S2 be the sum of first 4nterms of thesame arithmetic progression. If (S2−S1)is 1000 , then the sum of the first 6n terms of the arithmeticprogression is equal to:
(1)1000
(2)7000
(3)5000
(4)3000
95.
If tanB=sin(A+C)2sinAsinC, then tanA,tanB and tanC are in
(1)Arithmetic progression
(2)Harmonic progression
(3)Geometric progression
(4)Arithmetico - geometric progression
96.
The sum of the series, 2⋅31⋅2+3⋅42⋅22+4⋅53⋅23+ to n terms is
(1)n+22n+1+1
(2)n+22n+1−1
(3)n+22n+1+2
(4)n+22n+1−2
97.
Let the arithmetic mean of a1 and b1 be 165,a>2. If α is such that a,4,α,b are n A.P., then the equation αx2−ax+2(α−2b)=0 has:
(1)one root in (0,2) and another in (−4,−2)
(2)one root in (1,4) and another in (-2,0)
(3)both roots in the interval (−2,0)
(4)complex roots of magnitude less than 2
98.
If logea,logeb,logec are in an A.P. and logea−loge2b,loge2b−loge3c,loge3c−logea are also in an A.P, then a:b:c is equal to
(1)9:6:4
(2)16:4:1
(3)25:10:4
(4)6:3:2
99.
If a,b,c are three consecutive terms of an A.P. and x,y,z are three consecutive terms of a G.P, then the value of xb−c⋅yc−a⋅za−b is
(1)0
(2)xyz
(3)-1
(4)1
100.
Five numbers are in A.P., whose sum is 25 and product is 2520 . If one of these five numbers is −21, then the greatest number amongst them is :
(1)221
(2)16
(3)5
(4)7
101.
2⋅51+5⋅81+8⋅111+…….+(3n−1)(3n+2)1=
(1)6n−4n
(2)6n+3n
(3)6n+4n
(4)6n+4n+1
102.
If the set R=(a,b):a+5b=42,a,b∈N has m elements and ∑n=1m(1−in!)=x+iy, where i=−1, then the value of m+x+y is
(1)12
(2)4
(3)8
(4)5
103.
For x∈R,let[x] denote the greatest integer ≤x,then the sum of the series (−31)+(−31−1001)+(−31−1002)+⋯+(−31−10099) is
(1)−153
(2)−133
(3)−131
(4)−135
104.
If the sum of n terms of an A.P. is given by Sn=n2+n, then the common difference of the A.P. is
(1)1
(2)2
(3)6
(4)4
105.
32−11+52−11+72−11+…+(201)2−11 is equal to
(1)404101
(2)10125
(3)408101
(4)40099
106.
The sum (123×13+12+225×(13+23)+12+22+327×(13+23+33))+…… upto10thterm, is :
(1)680
(2)600
(3)660
(4)620
107.
If x=103+10.153.7+10.15.203.7.9+…. , then 5x+8=
(1)3355
(2)355
(3)533
(4)33255
108.
If |x|<1,|y|<1 and x=y, then the sum to infinity of the following series (x+y)+(x2+xy+y2)+(x3+x2y+xy2+y3)+…… is
(1)(1+x)(1+y)x+y+xy
(2)(1−x)(1−y)x+y−xy
(3)(1+x)(1+y)x+y−xy
(4)(1−x)(1−y)x+y+xy
109.
The common difference of theA.P.b1,b2,…,bm is 2more than the common difference of A.P.a1,a2,…,an if a40=−159,a100=−399 and b100=a70 then b1is equal to:
(1)−127
(2)−81
(3)127
(4)81
110.
The 20th term from the end of the progression 20,1941,1821,1743,…,−12941 is :-
(1)-118
(2)-110
(3)-115
(4)-100
111.
Consider an A. P. of positive integers, whose sum of the first three terms is 54 and the sum of the first twenty terms lies between 1600 and 1800. Then its 11th term is:
(1)90
(2)84
(3)122
(4)108
112.
If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to
(1)7
(2)4
(3)5
(4)6
113.
The minimum value of2sinx+2cosx is:
(1)2−1+2
(2)21−2
(3)21−21
(4)2−1+21
114.
If the roots of x3+ax2+bx+c=0 are in arithmetic progression with common difference 1 , then
(1)9c=a(b−2)
(2)9c=a(2−b)
(3)9c−a2(b−2)=0
(4)9c−a2(2−b)=0
115.
If 1+(1−22⋅1)+(1−42⋅3)+(1−62⋅5)+……+(1−202⋅19)=α−220β then an ordered pair(α,β)is equal to :
(1)(10,103)
(2)(10,97)
(3)(11,97)
(4)(11,103)
116.
The number of terms common the two A.P.3,7,11,…,407 and 2,9,16,…,709 is
117.
If the arithmetic mean and geometric mean of the pth and qth terms of the sequence −16,8,−4,2,……… satisfy the equation 4x2−9x+5=0, then p+q is equal to
118.
The sum of first four terms of a geometric progression (G.P.) is 1265and the sum of their respective reciprocals is 1865 . If the product of first three terms of the G.P. is 1, and the third term is α, then 2α is
119.
The sum ∑k=120(1+2+3+⋯+k) is
120.
The sum 1⋅12−2⋅32+3⋅52−4⋅72+5⋅92−⋯+15⋅292 is ________