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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Sequence & Series · Set 5 (Q121-150)
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121.
If the sum of the first 20 terms of the series 4+3⋅12+144⋅1+4+3⋅22+244⋅2+4+3⋅32+344⋅3+4+3⋅42+444⋅4 is nm, where m and n are coprime, then m+n is equal to:
(1)423
(2)421
(3)422
(4)420
122.
The sum of the infinite series 1+65+6212+6322+6435+6551+6670+.... is equal to:
(1)216425
(2)216429
(3)125288
(4)125280
123.
Let the sum of the first n terms of a non-constant A.P.,a1,a2,a3,………… be 50n+2n(n−7)A where A is aconstant. If d is the common difference of this A.P., then the ordered pair (d,a50) is equal to:
(1)(50,50+46A)
(2)(50,50+45A)
(3)(A,50+45A)
(4)(A,50+46A)
124.
Consider an infinite geometric series with first term ' a ' and common ratio ' r '. If the sum is 4 and the second term is 43, then
(1)a=2,r=83
(2)a=74,r=73
(3)a=23,r=21
(4)a=3,r=41
125.
The nth term of the series 1+3+7+13+21+… is 9901 . The value of n is
(1)90
(2)100
(3)99
(4)900
126.
If an=4n2−16n+15−2, then a1+a2+…+a25 is equal to
(1)14451
(2)13849
(3)14150
(4)14752
127.
12+(12+22)+(12+22+32)+…+ (12+22+…+n2)=
(1)12n(n+1)(n+2)
(2)6n(n+1)(2n+1)
(3)12n(n+1)2(n+2)
(4)12n(n+1)(n+2)(n+3)
128.
For any three positive real numbers a, b and c, 9(25a2 + b2) + 25(c2 – 3ac) = 15b(3a + c), Then
(1)b , c and a are in G.P.
(2)b, c and a are in A.P.
(3)a, b and c are in A.P.
(4)a, b and c are in G.P.
129.
If the sum of the first 15 terms of the (43)3+(121)3+(241)3+33+(343)3+…… is equal to 225k then k is eaual to:
(1)108
(2)27
(3)54
(4)9
130.
The sum of the series 1+2×3+3×5+4×7+…upto11th term is:
(1)915
(2)946
(3)945
(4)916
131.
Let a,ar,ar2, be an infinite G.P. If ∑n=0∞arn=57 and ∑n=0∞a3r3n=9747, then a+18r is equal to
(1)46
(2)38
(3)31
(4)27
132.
If the sum of the second, fourth and sixth terms of a G.P. of positive terms is 21 and the sum of its eighth, tenth and twelfth terms is 15309, then the sum of its first nine terms is:
(1)757
(2)755
(3)750
(4)760
133.
Let a,b and c be in G.P. with common ratio r, where a=0 and 0<r<21. If 3a,7b and 15c are the first three terms of an A.P., then the 4th term of this A.P. is :
(1)32a
(2)5a
(3)37a
(4)a
134.
The sum of the following series 1+6+79(12+22+32)+912(12+22+32+42)+1115(12+22+….+52)+… up to 15 terms, is:
(1)7520
(2)7510
(3)7830
(4)7820
135.
If the sum of the first 40 terms of the series, 3+4+8+9+13+14+18+19+… is (102)m, then m is equal to:
(1)20
(2)25
(3)10
(4)5
136.
Let the greatest common divisor of m,n be 1 . If 1.71+7.131+13.191+…. upto 20 terms =nm, then 5m+2n=
(1)325
(2)330
(3)342
(4)337
137.
If ∑r=1nTr=64(2n−1)(2n+1)(2n+3)(2n+5), then limn→∞∑r=1n(Tr1) is equal to:
(1)0
(2)32
(3)1
(4)31
138.
Let a1,a2,…,a10 be a G.P. If a1a3=25, then a5a9 equals :
(1)54
(2)4(52)
(3)53
(4)2(52)
139.
Let an be the nth term of an A.P. If Sn=a1+a2+a3+…+an=700, a6=7 and S7=7, then an is equal to:
(1)65
(2)56
(3)70
(4)64
140.
If f:R→R is defined by f(x+y)=f(x)+f(y)∀x,y∈R and f(1)=7, then ∑r=1nf(r)=
(1)43n(n+2)
(2)2n(n−1)
(3)27n(n+1)
(4)4(n+1)(n+2)
141.
The product of three consecutive terms of a G.P. is 512 . If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is:
(1)36
(2)32
(3)24
(4)28
142.
Let a1,a2,…anbe a given A.P. whose common difference is an integer and Sn=a1+a2+…+an If a1=1,an=300 and 15≤n≤50then the ordered pair(Sn−4,an−4) is equal to
(1)(2490,249)
(2)(2480,249)
(3)(2490,248)
(4)(2480,248)
143.
The interior angles of a polygon with n sides, are in an A.P. with common difference 6∘. If the largest interior angle of the polygon is 219∘, then n is equal to
144.
The value of (0.16)log2.5(31+321+331+...of∞) is equal to
145.
If three successive terms of a G.P. with common ratio r(r>1) are the lengths of the sides of a triangle and [r] denotes the greatest integer less than or equal to r, then 3[r]+[−r] is equal to :
146.
Let the first term of a series be T1=6 and its rth term Tr=3Tr−1+6r,r=2,3, n. If the sum of the first n terms of this series is 51(n2−12n+39)(4⋅6n−5⋅3n+1), then n is equal to______
147.
Let a1=b2=1 and an=an−1+(n−1),bn=bn−1+an−1∀n≥2. If S=∑2nbn and T=∑2n−1n, then 27(2S−T) is equal to ______
148.
If (α+11+α+21+……+α+10121)−(2⋅11+4⋅31+6⋅51+……+2024⋅20231)=20241, then α is equal to______
149.
If 1.3+2.5+3.7+…uptonterms13+23+33+…uptonterms=59, then the value of n is
150.
If 1+233−2+185−26+36393−112+18049−206+… upto ∞=2+(ab+1)loge(ba), where a and b are integers with gcd(a,b)=1, then 11a+18b is equal to_______