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JEE Previous Year Question

$lim x \to 2 \frac{x ^{3} - x ^{2} - x - 2}{2 x ^{3} - 3 x ^{2} - 3 x + 2} =$

Topic: JEE PYQ

Answer: D. Full step-by-step solution below.

A $0$
B $\infty$
C $\frac{5}{7}$
D $\frac{7}{9}$

Correct answer: D

Solution

(d) Given lim_{x \to 2} \frac{x ^{3} - x ^{2} - x - 2}{2 x ^{3} - 3 x ^{2} - 3 x + 2} (\frac{0}{0}) form} lim_{x \to 2} \frac{3 x ^{2} - 2 x - 1}{6 x ^{2} - 6 x - 3} = \frac{7}{9} {using L.H. rule}

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