Slope of a line passing through P (2 ,3 ) and intersecting the line x+y=7 at a distance of 4 units from P, is:

Question

Accepted Answer

Correct answer: B. (b) JEE Main 2019 Since point at 4 units from P (2 ,3 ) will be A(4 cos +2 ,4 sin( +3))and this point will satisfy the equation of line x+y=7 ⇒ cos + sin = 12 On squaring ⇒ sin2 - 34 ⇒ 2 tan 1+ tan^2 =- 34 ⇒3 tan^2 +8 tan +3=0 ⇒ tan = -8 2 76 (ignoring – ve sign) ⇒ tan = -8+2 76= 1- 71+ 7

$Slope of a line passing through P (2, 3) and intersecting the line x + y = 7 at a distance of 4 units from P, is:$

Solution

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