If the line passing through the points (5 ,1 ,a ) and (3 ,b ,1 ) crosses the YZ plane at the point (0 , 172 , -132 ), then a+b=

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Accepted Answer

Correct answer: B. (b) Equation of line through (5 ,1 ,a ) and (3 ,b ,1 ) is x-5 (5-3 )= y-11-b= z-aa-1= (say) Since this line passess through (0 , 172 , -132 ) Hence 0-55-3= ⇒ =- 52 and 172-11-b= = -52 ⇒b=4 and - 132-aa-1= =- 52 ⇒a=6 Therefore a+b=6+4=10

$If the line passing through the points (5, 1, a) and (3, b, 1) crosses the YZ plane at the point (0, \frac{17}{2}, \frac{- 13}{2}), then a + b =$

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