A point on the plane that passes through the points (1 ,-1, 6 ) , (0 ,0 ,7 ) and perpendicular to the plane x-2y+z=6 is

Question

Accepted Answer

Correct answer: B. (b) Equation of plane passes through the points (1 ,-1 ,6 ) , (0 ,0 ,7 ) and perpendicular to the plane x-2y +z=6 is (x-1y+1z-60-10+17-61-21)=0 ⇒(x-1y+1z-6-1111-21)=0 (x-1 ) (1+2 )- (y+1 ) (-1-1 )+ (z-6 ) (2-1 )=03 (x-1 )- (-2 ) (y+1 )+1 (z-6 )=03x-3+2y+2+z-6=03x+2y+z-7=0 Now, put all the points given in the options and verify it. The plane passes through (1 ,1 ,2 ).

$A point on the plane that passes through the points (1, - 1, 6), (0, 0, 7) and perpendicular to the plane x - 2 y + z = 6 is$

Solution

More Three-Dimensional Geometry PYQs