A value of (0, 3 ), for which vmatrix1+ ^2 & ^2 &4 6 \ ^2 &1+ ^2 &4 6 \ ^2 & ^2 &1+4 6 vmatrix=0 is:

Question

Accepted Answer

Correct answer: A. (a) JEE Main 2019 C_1 C_1+C_2 (2 sin^2 4 cos6 21+ sin^2 4 cos6 1 sin^2 1+4 cos6 )=0 R_1 R_1-R_2 ,R_2 R_2-R_3 (0-1011-11 sin^2 (1+4 cos6 ))=0 On expanding, we get 2+4 cos6 =0 cos6 =- 12 ∵ ∈ (0 , 3 ) ⇒6 ∈ (0 ,2 ) Therefore, 6 = 2 3 or 4 3 ⇒ = 9 or 2 9

$A value of θ \in (0, \frac{π}{3}), for which 1 + cos^{2} θ cos^{2} θ cos^{2} θ sin^{2} θ 1 + sin^{2} θ sin^{2} θ 4 cos 6 θ 4 cos 6 θ 1 + 4 cos 6 θ = 0 is:$

Solution

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