If (k ,1 ,5 ) , (1 ,0 ,3 ) , (7 ,-2 ,m ) are collinearr then (k ,m )=

Question

Accepted Answer

Correct answer: A. (a) ∵ Points (k ,1 ,5 ) , (1 ,0 ,3 ) \& (7 ,-2 , m ) are collinear. A ≡ (k ,1 ,5 ) ,B ≡ (1 ,0 ,3 ) ,C ≡ (7 ,-2 ,m ) AB= (1-k )i+ (0-1 )j-2k AC= (7-k )i-3j+ (m-5 )k AB= AC ⇒ (1-k )i-j-2k= [ (7-k )i-3j+ (m-5 )k ] Comparing both sides, we get 1-k= (7-k) … . . (i ) -1=-3 ⇒ = 13 … . ( ii ) -2= (m-5 ) ⇒-6=m-5 ⇒m=-1 from eqn. (i) ⇒1-k= 13 (7-k ) ⇒ 3-3k=7-k ⇒2k^3=-4 ⇒k=-2 ∴ (k ,m )= (-2 ,-1 )

$If (k, 1, 5), (1, 0, 3), (7, - 2, m) are collinearr then (k, m) =$

Solution

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