Let a=i+2j+k ,b=3 (i-j+k ). Let c be the vector such that a c=b and a c=3. Then a ( (c b )-b-c ) is equal to :

Question

Accepted Answer

Correct answer: B. (b) a [ (c b )-b-c ]a (c b )-a b-a c … (i ) givena c=b ⇒ (a c ) b=b b= |b |^2=27 ⇒a (c b)= (acb )=(a c) b=27 … ( ii ) Now a b=3-6+3=0...(iii) a c=3 … . . . ( iv ) ( given ) By (i), (ii), (iii) ∖ & (iv) 27-0-3=24

$Let a = i + 2 j + k, b = 3 (i - j + k) . Let c be the vector such that a \times c = b and a \cdot c = 3 . Then a \cdot ((c \times b) - b - c) is equal to :$

Solution

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