If ABCD is a cyclic quadrilateral with R as the radius of the circumcircle and ( AB )^2+ ( CD )^2=4R^2 then

Question

Accepted Answer

Correct answer: C. (c) We know that if △ BCD is a cyclic quadrilateral with R as the radius of the circumcircle and AB^2+ CD^2=4R^2 ∴ ABCD is a rhombus. ∴ ∠ AOB=90^ and ∠ COD=90^ ∴a b=0 and c d=0 So. a b+c .d=0

$If ABCD is a cyclic quadrilateral with R as the radius of the circumcircle and (AB)^{2} + (CD)^{2} = 4 R^{2} then$

Solution

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