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JEE Previous Year Question

$The alternating current is given by i = (42 sin (\frac{2 π}{T} t) + 10) A The r.m.s. value of this current is A.$

Topic: JEE PYQ

Answer: 11. Full step-by-step solution below.

Correct answer: 11

Solution

(11) f_{rms}^{2} = f_{1 ms}^{2} + f_{2 ms}^{2} = (\frac{42}{2})^{2} + 1 0^{2} = 121 \Rightarrow f_{ms} = 11 A

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