JEE Previous Year Question

The disintegration energy $Q$ for the nuclear fission of ${}^{235}U\to {}^{140}\text{Ce}+{}^{94}\text{Zr}+n$ is_______MeV . Given atomic masses of ${}^{235}U\text{:}235.0439u\text{;}{}^{140}\text{Ce}\text{:}139.9054u$, ${}^{94}\text{Zr}\text{:}93.9063u\text{;}n\text{:}1.0086u\text{,}$ Value of $c^2=931\text{MeV}/u$

Topic: JEE PYQ

Answer: 208. Full step-by-step solution below.