A body of mass 2kg moving with a speed of 4m/s. makes an elastic collision with another body at rest and continues to move in the original direction but with one fourth of its initial speed. The spee…

Question

A body of mass 2kg moving with a speed of 4m/s. makes an elastic collision with another body at rest and continues to move in the original direction but with one fourth of its initial speed. The speed of the two body centre of mass is x1 0m/s. Then the value of x is

Accepted Answer

Correct answer: 25. (25) p_i=p_f 2x4=2x1+m_2xv_2 m_2V_2=6 by coefficient of restitution 1= v_2−14⇒v_2=5 m/s by (i) m_2×5=6 m_2=1.2 k g v_e m= m_1v_1+m_2v_2m_1+m_2 v_c m= 2×1+1.2×52+1.2= 83.2= 2 51 0 x=25

$A body of mass 2kg moving with a speed of 4m/s. makes an elastic collision with another body at rest and continues to move in the original direction but with one fourth of its initial speed. The speed of the two body centre of mass is \frac{x}{10} m / s . Then the value of x is$

Solution

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