A solid circular disc of mass 50 kg rolls along a horizontal floor so that its center of mass has a speed of 0.4m/s. The absolute value of work done on the disc to stop it is J.

Question

Accepted Answer

Correct answer: 6. (6) Using work energy theorem W= KE=0-( 12 mv^2+ 12I ^2)W=0- 12 mv^2(1+ K^2R^2)=- 12 50 0.4^2(1+ 12)=-6J Absolute work=+6JW=-6J |W |=6J

$A solid circular disc of mass 50 kg rolls along a horizontal floor so that its center of mass has a speed of 0.4 m / s . The absolute value of work done on the disc to stop it is J.$

Solution

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