JEE Previous Year Question

A coil has an inductance of 2 H and resistance of 4. A 10 V is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be_____x 10-2 J

Topic: JEE PYQ

Answer: 625. Full step-by-step solution below.

Correct answer: 625

Solution

(625)
The data given is
L = 2H
R = 4
V = 10 V
Using Ohm's law, V = IR,

The energy of an inductor is given by

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