Nitrogen gas is at 300^ C temperature. The temperature (in K) at which the rms speed of a H_2molecule would be equal to the rms speed of a nitrogen molecule, is (Molar mass of N_2 gas 28g).

Question

Accepted Answer

Correct answer: 40.93. 40.93JEE Main 2020 V_ rms for N_2= 3 KT28= 3 K 57328 V_ rms for H_2= 3 KT_12 ∵V_ rms for N_2=V_ rms for H_2 ∴ 3 KT_12= 3K 57328 ⇒T_1= 57314K T_1=40.93 kelvin

$Nitrogen gas is at 300^{\circ} C temperature. The temperature (in K) at which the rms speed of a H_{2} molecule would be equal to the rms speed of a nitrogen molecule, is (Molar mass of N_{2} gas 28 g).$

Solution

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