The increase in pressure required to decrease the volume of a water sample by 0.2 \% is P 10^5 Nm^-2. Bulk modulus of water is 2.15 10^9 Nm^-2. The value of P is…..

Question

Accepted Answer

Correct answer: 43. (43) Since bulk modulus is given as B= - P ( vv ) 2.15 10^9= - P- ( 0.2100 ) P=2.15 10^9 2 10^-3 =4.3 10^6=43 10^5 N/m^2

$The increase in pressure required to decrease the volume of a water sample by 0.2 % is P \times 10^{5} Nm^{- 2} . Bulk modulus of water is 2.15 \times 10^{9} Nm^{- 2} . The value of P is\dots..$

Solution

More Mechanical Properties of Solids PYQs