The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02 \% is______ m. (Take density of sea water =10^3 kgm^-3, Bulk modulus of rubber =9 10^8 Nm^-2, a…

Question

The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02 \% is______ m. (Take density of sea water =10^3 kgm^-3, Bulk modulus of rubber =9 10^8 Nm^-2, and g=10 ms^-2 )

Accepted Answer

Correct answer: 18. (18) = - P VV P=- VV ρg h=- VV 10^3 10 h=-9 10^8 (- 0.02100) ⇒h=18 m

$The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02 % is______m . (Take density of sea water = 10^{3} kgm^{- 3}, Bulk modulus of rubber = 9 \times 10^{8} Nm^{- 2}, and g = 10 ms^{- 2})$

Solution

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