A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to 60^ . The refractive index of the prism material is 2. The angle of incidence (in degrees) is ____…

Question

A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to 60^ . The refractive index of the prism material is 2. The angle of incidence (in degrees) is ________.

Accepted Answer

Correct answer: 45. (45) To find the angle of incidence when a ray of light experiences minimum deviation in a prism, we use the formula for the refractive index : = sin ⁡ ( A+ _m2 ) sin ⁡ ( A2 ) Given: The angle of the prism, A=60^ The refractive index of the prism material, = 2 Minimum deviation, _m=30^ At minimum deviation, the angle of incidence i equals the angle of emergence e. Therefore, the relation between the angle of minimum deviation and the angle of the prism is represented as: _m=2i-A Solving for i : _m=2i-A ⟹30^ =2i-60^ ⟹2i= Thus, the angle of incidence is 45^ .

$A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to . The refractive index of the prism material is . The angle of incidence (in degrees) is ________.$

Solution

More Ray Optics PYQs