A particle executes simple harmonic motion represented by displacement function as x (t )=A sin( ωt+ ) If the position and velocity of the particle at t=0s are 2cm and 2 ωcms^-1respectively, then its…

Question

A particle executes simple harmonic motion represented by displacement function as x (t )=A sin( ωt+ ) If the position and velocity of the particle at t=0s are 2cm and 2 ωcms^-1respectively, then its amplitude is x 2 cm where the value of x is

Accepted Answer

Correct answer: 2. (2) x (t )=A sin( ωt+ ) v (t )= Aω cos( ωt+ ) 2=A sin …..(1) 2 =2 cos …..(2) From (1) and (2) tan =1 Putting value of in equation (1) 2=A ( 1 2 ) A=2 2 X=2

$A particle executes simple harmonic motion represented by displacement function as x (t) = A sin (ωt + φ) If the position and velocity of the particle at t=0s are 2cm and 2 ωcm s^{- 1} respectively, then its amplitude is x 2 cm where the value of x is$

Solution

More Simple Harmonic Motion PYQs