A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3.14 s. The maximum force exerted by spring on block is___N.

Question

Accepted Answer

Correct answer: 20. (20) By Newton's second law, F = ma_max. The maximum acceleration for a SHM is given by a_max = ω2A ...(i) The time period is given by T= 2 = 3.14s ⇒ = 2 T= 2 3.14=2 rads^-1 Thus, the maximum acceleration from equation (i) a_ max=4 1=4ms^-2 The maximum force is F = 5 kg x 4 m s^-2 = 20 N

$A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3.14 s. The maximum force exerted by spring on block is___N.$

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