When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is x8, where x=_______

Question

Accepted Answer

Correct answer: 9. (9) Let total energy=E= 12 KA^2 U= 12 K ( A3 )^2= KA^22 9= E9 KE=E- E9= 8E9 Ratio Total KE= E 8E9= 98 x=9

$When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is \frac{x}{8}, where x =_______$

Solution

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