The internal energy of air in 4 m 4 m 3 m sized room at 1 atmospheric pressure will be _________ 10^6 J (Consider air as diatomic molecule)

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Accepted Answer

Correct answer: 12. (12) To determine the internal energy of the air in a room that measures 4 m 4 m 3 m at 1 atmospheric pressure, we can follow these steps using the properties of a diatomic gas: The volume of the room, V, is calculated as: V=4 m 4 m 3 m=48 m^3 For a diatomic gas like air, the internal energy U is given by the formula: U=nC_vT=n 5 RT2 Where: n is the number of moles, C_v is the molar heat capacity at constant volume, R is the ideal gas constant, and T is the temperature in Kelvin. Using the ideal gas law, PV= nRT, we can substitute for nRT : nRT= PV Therefore, the internal energy U becomes: U= 52 PV Substituting the given values for atmospheric pressure P=10^5 Pa (1 atm) and volume V=48 m^3 : U= 52 10^5 Pa 48 m^3=12 10^6 J Thus, the internal energy of the air in the room is 12 10^6 J.

$The internal energy of air in 4 m \times 4 m \times 3 m sized room at 1 atmospheric pressure will be _________\times 10^{6} J (Consider air as diatomic molecule)$

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