A man whose father was colour blind marries a woman who had a colour blind mother and normal father. What percentage of male children of this couple will be colour blind ?

Question

Accepted Answer

Correct answer: C. (c) The man is normal (XᴺY) because a son inherits the Y chromosome from his father, not the X chromosome. The woman, having a colour-blind mother (X^CX^C) and a normal father (X^NY), must be a carrier (X^NX^C). Cross: X^NY × X^NX^C Among the sons, 50% will be X^CY (colour blind) and 50% will be X^NY (normal).

$A man whose father was colour blind marries a woman who had a colour blind mother and normal father. What percentage of male children of this couple will be colour blind ?$

Solution

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