JEE · NEET Previous Year Question
Which of the following statements are TRUE about Haloform reaction?:(A) Sodium hypochlorite reacts with KI to give KOI .(B) KOI is a reducing agent.(C) -unsaturated methylketone will give iodoform reaction.(D) Isopropyl alcohol will not give iodoform test.(E) Methanoic acid will give positive iodoform test.
Choose the correct answer from the options given below:
Topic: JEE PYQ
Answer: C. Full step-by-step solution below.
- A(A), (C) & (E) Only
- B(B), (D) & (E) Only
- C(A) & (C) Only
- D(A), (B) & (C) Only
Correct answer: C
Solution
(c) In the haloform reaction:(A) Sodium hypochlorite reacts with KI in acidic medium to generate the active halogenating species, forming KOI (potassium iodite/hypoidite). TRUE.
(B) KOI serves as an oxidizing agent (not reducing) in the reaction, converting methyl ketones to carboxylic acids. FALSE.
(C) -unsaturated methylketones possess the essential methyl ketone group ( ) required for haloform reaction, allowing iodination and subsequent cleavage. TRUE.
(D) Isopropyl alcohol lacks a methyl ketone group, so it cannot undergo the haloform reaction. TRUE.
(E) Formic acid has no methyl ketone functionality, preventing haloform test. FALSE.
Therefore, statements A and C are true.
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