What is the wave number of photon emitted during transition from orbit, n=4 to n=2 in hydrogen atom (R_H=109677 cm^-1) ?

Question

Accepted Answer

Correct answer: A. (a) n_1=2 ;n_2=4 ,Z=1 v= 1 =RZ^2( 1n_1^2- 1n_2^2) v= Wave number, = Wavelength, R= Rydberg constant, Z= Atomic number, n_1= Lower energy level, n_2= Higher energy level v=109677 1^2( 12^2- 14^2)v=109677 316=20564.44 cm^-1

$What is the wave number of photon emitted during transition from orbit, n = 4 to n = 2 in hydrogen atom (R_{H} = 109677 cm^{- 1}) ?$

Solution

More Atomic Structure PYQs