The de Broglie wavelength of an electron travelling with $20 %$ of velocity of light is
$(h = 6.626 \times 10^{- 34} Js; m_{e} = 9.1 \times 10^{- 31} kg)$

Question

The de Broglie wavelength of an electron travelling with 20 \% of velocity of light is (h=6.626 10^-34 Js ;m_e=9.1 10^-31 kg)

Accepted Answer

Correct answer: B. (b) C=3 10^8 ms^-1 ⇒ Velocity (V )= 20 3 10^8100=6 10^7 ms^-1. Thus, = hm_eV= 6.626 10^-34(9.1 10^-31)(6 10^7)=1.2 10^-11 m

$The de Broglie wavelength of an electron travelling with 20 % of velocity of light is (h = 6.626 \times 10^{- 34} Js; m_{e} = 9.1 \times 10^{- 31} kg)$