The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097 × 10^7 m^–1)

Question

Accepted Answer

Correct answer: A. (a) 1 = R ( 1n_1^2- 1n_2^2) ⇒ 1 = 1.097 × 107 m^–1 ( 11^2- 1 ^2) ∴ λ = 91 × 10–9 m = 91 m.

$The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097 \times 1 0^{7} m^{-1})$

Solution

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