The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a_0 is Bohr radius]:

Question

Accepted Answer

Correct answer: C. (c) Nuclear attraction on the electron=Centrifugal force kZe^2r^2= mv^2rv^2= kZe^2 mr … (i ) Angular momentum, mvr=n h2 v^2= n^2h^24 ^2m^2r^2 … ( ii ) Comparing (i) and (ii) kZe^2 mr= n^2h^24 ^2m^2r^2r= n^2Z ( h^24 πmke^2 )= n^2a_0Z ∴v_n= hZ2 a_0n KE= 12mv_n^2= h^2Z^28 ^2ma_0^2n^2 KE ( forn=2 ,Z=1 )= h^232 ^2ma_0^2 .

$The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a_{0} is Bohr radius]:$

Solution

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