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JEE · NEET Previous Year Question

$The calculated bond order of superoxide ion (O_{2}^{-})$

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

A $1.5$
B $1$
C $2.5$
D $2$

Correct answer: A

Solution

(a) : The bond order of superoxide ion O_{2}^{-} is O_{2} \to σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} \approx π 2 p_{y}^{2} π^{*} 2 p_{x}^{2} \approx π^{*} 2 p_{y}^{1} Bond order = 1/2 (N_{b} - N_{a}) = 1/2 [10 - 7] = 1.5

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