According to Bayer's strain theory which is highly stable?

Question

Accepted Answer

Correct answer: B. (c) : Bayer's strain theory : The amount of strain is directly proportional to the angle through which a valency bond has deviated from its normal position i.e. amount of deviation (d). d= 12(109^ 28^ '- valency angle) In cyclobutane, d= 12(109^ 28^ '-90^ )=9^ 44^ ' In cyclopentane, d= 12(109^ 28^ '-108^ )=0^ 44^ ' In cyclohexane, d= 12(109^ 28^ '-120^ )=-5^ 16^ ' In cycloheptane, d= 12(109^ 28^ '-135^ )=-9^ 33^ ' Cyclopentane is more stable and less reactive compared to cyclobutane; and cyclohexane and cycloheptane are free from angle of strain. Therefore quite stable. But actually Bayer's theory fails for the rings containing six or more carbon atoms.

$According to Bayer's strain theory which is highly stable?$

Solution

More Hydrocarbons PYQs