How many millilitres of 20 volume H_2O_2 solution is needed to react completely with 500 mL of acidified 1N KMnO_4 solution?

Question

Accepted Answer

Correct answer: C. (c) Given, normality of KMnO_4 (N_1 )=1 N Volume of KMnO_4 (V_1 )=500 mL Normality of H_2O_2 (N_2 )= Volume strength5.6 ( eq . mass )= 205.6=3.5 Now, N_1V_1 ( KMnO_4 )=N_2V_2 (H_2O_2 ) 1 500=3.57 ⇒ V_2= 5003.57=140 mL

$How many millilitres of 20 volume H_{2} O_{2} solution is needed to react completely with 500 mL of acidified 1 N KMnO_{4} solution?$

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