What quantity (in mL) of a 45% acid solution of a mono-protic strong acid must be mixed with a 20% solution of the same acid to produce 800 mL of a 29.875% acid solution ?

Question

Accepted Answer

Correct answer: B. (b) Let volume of 1st solution = Vml \ Volume of 2nd solution = (800–V) mL Amount of acid in 1st solution + Amount of acid in 2nd solution = Amount of acid in obtained solution. \ 45 V100+ 20 (800-V )100= 29.875 (800 )100 \ V= 316

$What quantity (in mL) of a 45% acid solution of a mono-protic strong acid must be mixed with a 20% solution of the same acid to produce 800 mL of a 29.875% acid solution ?$

Solution

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