The molar solubility(s) of zirconium phosphate with molecular formula $(Zr^{4 +})_{3} (PO_{4}^{3 -})_{4}$ is
given by relation:

Question

The molar solubility(s) of zirconium phosphate with molecular formula ( Zr^4+ )_3 ( PO_4^3- )_4 is given by relation:

Accepted Answer

Correct answer: B. (b) Zr_3 ( PO_4 )_4 (s ) ⇌3 Zr^+4 ( aq )+4 PO_4^-3 ( aq ) 3s 4s K_ sp= (3s )^3 (4s )^4=6912 s^7 s= ( K_ sp6912 )^1/7

$The molar solubility(s) of zirconium phosphate with molecular formula (Zr^{4 +})_{3} (PO_{4}^{3 -})_{4} is given by relation:$