Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (K_a = 1.0 × 10^–5) will be:

Question

Accepted Answer

Correct answer: D. (d) Given : K_a=1.0 10^-5 ,C=0.1M First find K_b :K_b= K_wK_a= 10^-1410^-5=10^-9 For weak base : ( OH^- )= K_b C= 10^-9 10^-1= 10^-10=10^-5 So : pOH=5 ⇒ pH=14-5=9

$Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (K_{a} = 1.0 \times 1 0^{-5}) will be:$

Solution

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