What is the molar solubility of Al ( OH )_3 in 0.2 MNaOHsolution? Given that, solubility product of Al ( OH )_3=2.4 10^-24:

Question

Accepted Answer

Correct answer: C. (c) Let the solubility of Al ( OH )_3 in 0.2 MNaOH solution be s Then, Al ( OH )_3 ⇌ Al^3+s+3 OH^-3s and NaOH0.2M ⇌ Na^+0.2M+ OH0.2M ( Al^3+ )=s and ( OH^- )=3s+0.2 ≈0.2 K_ sp=2.4 10^-24= ( Al^3+ ) [ OH ]^3 2.4 10^-24=s (0.2 )^3 s= 2.4 10^-248 10^3=3 10^-22 mol/L

$What is the molar solubility of Al (OH)_{3} in 0.2 MNaOH solution? Given that, solubility product of Al (OH)_{3} = 2.4 \times 10^{- 24} :$

Solution

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