The number of neutrons present in the more abundant isotope of boron is ' x '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' y '. The value of x+y…

Question

The number of neutrons present in the more abundant isotope of boron is ' x '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' y '. The value of x+y is _______

Accepted Answer

Correct answer: B. (b) More abundant isotope =B^11 [Number of neutrons =6 ] x=6 B+O_2 B_2O_3 Oxidation state of B in B_2O_3=+3 So, y=3 Hence x+y=9

$The number of neutrons present in the more abundant isotope of boron is ' x'. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' y'. The value of x + y is _______$

Solution

More p-Block Elements PYQs