The first ionisation energies (in kJ mol^-1 ) of four consecutive elements of the second period are given in the options. The first ionisation energy of nitrogen is

Question

Accepted Answer

Correct answer: B. (b) Option (c) has the highest ionisation energy I E_1 1681 kJ mol^-1 among the given value hence it cannot be the I E_1 of N. It is the I E_1 of ' F '. Option (a) has the lowest I E_1 (1086 kJ mol^-1 ). Hence, it cannot be I E_1 of N. If we compare (b) and (d) then (b) has higher I E_1 then (d) which can be compared with I-E of N and O. Since nitrogen has half filled stable. Electronic configuration so, it must have higher I E_1 than that of oxygen. Hence, (b) is correct answer i.e., 1402 kJ mol^-1 is I E_1 of nitrogen.

$The first ionisation energies (in kJ mol^{- 1}) of four consecutive elements of the second period are given in the options. The first ionisation energy of nitrogen is$

Solution

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