In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm Hg pressure. The percentage composition of nitrogen in th…

Question

In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm Hg pressure. The percentage composition of nitrogen in the compound (Aqueous tension at 300 K=15 mmHg) is \%.

Accepted Answer

Correct answer: B. (b) To determine the percentage composition of nitrogen using Dumas' method, follow these calculations: Calculate the Pressure of Nitrogen Gas: Pressure of N_2=(715 mmHg-15 mmHg)=700 mmHg Calculate the Moles of Nitrogen (n_N_2 ) : n_N_2= PV RTWhere: P=700 mmHg V=60 10^-3 L R=0.0821 L atm/ molK T=300 K Plug the values into the equation: n_N_2= 700 60 10^-3760 0.0821 300 ≈2.24 10^-3 mol Calculate the Mass of Nitrogen Gas: Mass of N_2=2.24 10^-3 mol 28 g/ mol=0.06272 g Determine the Percentage Composition of Nitrogen: \% N_2= ( 0.062720.5 ) 100 ≈12.57 \% Thus, the percentage composition of nitrogen in the compound is approximately 12.57 \%.

$In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm Hg pressure. The percentage composition of nitrogen in the compound (Aqueous tension at 300 K = 15 mmHg) is % .$

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